Question 321696
Three consecutive whole numbers are such that the square of the middle number
 is greater than the product of the other two by 1.
 Find the middle number:
There is no unique solution
:
let x = the middle number
then
(x-1) = the 1st number
and
(x+1) = the 3rd number
:
x^2 = ((x-1)*(x+1)) + 1
FOIL
x^2 = x^2 - 1 + 1
:
x^2 = x^2
Which means this is true for any 3 consecutive numbers even, -1, 0 +1
:
Try a few like; 142, 143, 144: 143^2 = 20449, 142*144 = 20448