Question 321735
Well, you should know that with h(x), x is a variable. So you just substitute:
a)h(x)= 3x^2+5
h(0) means that x=0
plug in the values and use the order of operations:
    h(0)=3(0)^2+5
        =3(0)+5
        =0+5
        =5
b)h(x)= 3x^2+5
h(-1) means that x=-1
plug in the values and use the order of operations:
    h(-1)=3(-1)^2+5
        =3(1)+5
        =3+5
        =8
c)h(x)= 3x^2+5
h(4) means that x=4
plug in the values and use the order of operations:
    h(4)=3(4)^2+5
        =3(16)+5
        =48+5
        =53
d)h(x)= 3x^2+5
h(-3) means that x=-3
plug in the values and use the order of operations:
    h(-3)=3(-3)^2+5
        =3(9)+5
        =27+5
        =32
a)h(x)= 3x^2+5
h(4b) means that x=4b
just because there is a letter/variable does not mean that you change how it is done
plug in the values and use the order of operations:
    h(4b)=3(4b)^2+5
        =3(16b^2)+5
        =(48b^2)+5