<PRE><B>Question 321553</B>
solve the radical equation algebraically and check for extraneous solutions 
the square root of 3x-2=x-4
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sqrt(3x-2) = x-4
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Square both sides:
3x-2 = x^2-8x+16
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x^2-11x+18 = 0
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(x-2)(x-9) = 0
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x = 2 or x = 9
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Check solutions in the original equation: 
sqrt(3x-2) = x-4
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x = 2 ?
sqrt(4) = 2-4 
False
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x = 9 ?
sqrt(25) = 9-4
True
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Final Solution: x = 9
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Cheers,
Stan H.
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