Question 321486
{{{root(3,y^13)*root(3,16y^14)=root(3,(y^13)(16y^14))=root(3,16y^27)=root(3,8*2*(y^9)^3)=root(3,8)*root(3,2)*root(3,(y^9)^3)=2*root(3,2)*y^9=2y^9*root(3,2)}}}



So {{{root(3,y^13)*root(3,16y^14)=2y^9*root(3,2)}}}