Question 321453
There are 4 even digits: 2,4,6,8

There are 4 choices for the first place, the second place, and the third place

4*4*4=64 three digit numbers that have all even digits.


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There are 4!/2!=12 ways to place the vowels on the ends:
ae,ai,au,ea,ei,eu,ia,ie,iu,ua,ue,ui

Place them and arrange the 6 inside letters in 6!/2! ways.

We divide by 2 because of the repeated 't'.

So, the number of ways is 12*(6!/2!)=4320 ways