Question 321316
# 1




{{{5x-2y=-8}}} Start with the given equation.



{{{-2y=-8-5x}}} Subtract {{{5x}}} from both sides.



{{{-2y=-5x-8}}} Rearrange the terms.



{{{y=(-5x-8)/(-2)}}} Divide both sides by {{{-2}}} to isolate y.



{{{y=((-5)/(-2))x+(-8)/(-2)}}} Break up the fraction.



{{{y=(5/2)x+4}}} Reduce.



So the equation {{{y=(5/2)x+4}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=5/2}}} and the y-intercept is {{{b=4}}} note: the y-intercept is the point *[Tex \LARGE \left(0,4\right)]



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# 2


<h4>y-intercept</h4>

To find the y-intercept, plug in {{{x=0}}} and solve for y



{{{3x + 2y = 11}}} Start with the given equation.



{{{3(0) + 2y = 11}}} Plug in {{{x=0}}}.



{{{0 + 2y = 11}}} Multiply {{{3}}} and 0 to get 0.



{{{ 2y = 11}}} Simplify.



{{{y=(11)/(2)}}} Divide both sides by {{{2}}} to isolate {{{y}}}.



So the y-intercept is *[Tex \LARGE \left(0,\frac{11}{2}\right)].