Question 321162
Two cyclist, 90 mi apart, start riding toward each other at the same time. One cycles twice as fast as the other. If they meet 2 h later, at what average speed is each cyclist traveling?
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let the speed of one cyclist be x mph
the other will be 2x mph
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They both travel for 2 hours before they meet.
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distance traveled by one + distance traveled by other = Total distance between them when starting.
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2x+2*2x=90
2x+4x=90
6x=90
x=15 mph the speed of first cyclist.
The speed of second cyclist will be 2x = 2*15=30 mph