Question 321157
7x+8y-12=0
8y=-7x+12
y=-7/8 x +12/8
..
slope = -7/8
the perpendicular to this line will have a slope of of 8/7
This line passes through (-2,5)
equation of line in slope intercept form =
y-y1= m(x-x1) 
y-(-2)= 8/7(x-5)
y+2=8/7(x-5)
7(y+2)=8(x-5)
7y+14=8x-40
7y=8x-56
y=(8/7)x -8 is the equation of the required line