Question 321134
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \log(x\,+\,9)\ -\ \log(2)\ =\ \log(5x\,+\,1)]


The difference of the logs is the log of the quotient.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \log\left(\frac{x\,+\,9}{2}\right)\ =\ \log(5x\,+\,1)]


If two logs are equal then their arguments must be equal.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{x\,+\,9}{2}\ =\ 5x\,+\,1]


Just solve for *[tex \Large x]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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