<PRE><B>Question 321075</B>
2r - 3s = 12
3r + 2s = 31
solve by the elimination method 
:
Multiply the 1st equation by 2, multiply the 2nd equation by 3, results:
4r - 6s = 24
9r + 6s = 93
----------------Addition eliminates s, find r
13r = 117
r = {{{117/13}}}
r = 9
:
Use the 2nd original equation to find s, substitute 9 for r
3(9) + 2s = 31
27 + 2s = 31
2s = 31 - 27
2s = 4
s = {{{4/2}}}
s = 2
:
The r,s ordered pair: 9, 2
:
:
Check solutions in the 1st original equation, substitute for r and s
2r - 3s = 12
2(9) - 3(2) = 
18 - 6 = 12, confirms our solutions</PRE>