Question 320153
{{{2x+3y<=6}}}
{{{3y<=-2x+6}}} 
{{{ y<=-(2/3)x+2 }}}
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Graph the line {{{y=-(2/3)x+2}}},
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{{{graph(300,300,-5,5,-5,5,-(2/3)x+2)}}}
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Choose a point not on the line and test the inequality.
(0,0) is a good choice.
{{{0<=-(2/3)(0)+2}}}
{{{2<=0}}}
True, (0,0) is in the solution region.
Shade the region containing (0,0) including the line.
*[invoke plot_any_inequality "y<=-(2/3)x+2", -5, 5, -5, 5, 300, 300]