Question 319934
{{{ (4^x)(3^(x+1))=2}}}
{{{(4^x)(3^x)3=2}}}
{{{12^x=2/3}}}
{{{x=log(12,(2/3))}}}
{{{highlight(x=log(2/3)/log(12))}}} or approximately,
{{{x=-0.1761/1.0792}}}
{{{x=-0.1632}}}