Question 321005
{{{a^2+2a+1=(a+1)^2}}}   
{{{a^2+6a+5=(a+1)(a+5)}}}
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A common denominator would be {{{(a+1)^2(a+5)}}},
{{{  a/(a^2+2a+1)+2/(a^2+6a+5)=(a(a+5)+2(a+1))/(a+1)^2(a+5))}}}
{{{  a/(a^2+2a+1)+2/(a^2+6a+5)=(a^2+5a+2a+2)/(a+1)^2(a+5))}}}
{{{  a/(a^2+2a+1)+2/(a^2+6a+5)=highlight((a^2+7a+2)/(a+1)^2(a+5)))}}}