Question 319807
{{{sqrt(2x^2 + 7x) = x + 2}}}
{{{2x^2+7x=(x+2)^2}}}
{{{2x^2+7x=x^2+4x+4}}}
{{{x^2+3x-4=0}}}
{{{(x+4)(x-1)=0}}}
Two solutions:
{{{x+4=0}}}
{{{x=-4}}}
.
.
.
{{{x-1=0}}}
{{{x=1}}}