Question 320811
{{{f(x)=x^2-x+1}}}
{{{f(0)=0^2-0+1}}}
{{{f(0)=1}}}
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{{{f(x)=x^2-x+1=0}}}
Use the quadratic formula,
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (-(-1) +- sqrt((-1)^2-4*1*1 ))/(2*1) }}}
{{{x = (1 +- sqrt(1-4 ))/2 }}}
{{{x = (1 +- sqrt(-3 ))/2 }}}
{{{highlight(x = (1 +- sqrt(3)i)/2) }}} where {{{i=sqrt(-1)}}}