Question 320906
The three consecutive odd integers are {{{N}}},{{{N+2}}}, and {{{N+4}}}.
Take the cube root of 35805 to get near the middle integer.
{{{root(3,35805)=32.959}}}
{{{N+2=33}}}
Find the average,
{{{A=(N+N+2+N+4)/3}}}
{{{A=(3N+6)/3}}}
{{{A=N+2}}}
{{{A=33}}}
The average of the three numbers is 33.