Question 320745
If x and y are positive consecutive odd integers, where y > x. which of the following is equal to y^2-x^2?
Then y = (x+2) 
:
Substitute for y
(x+2)^2 - x^2
FOIL
x^2 + 4x + 4 - x^2
x^2 - x^2 + 4x + 4
then
4x + 4 = y^2 - x^2
: