Question 320866
The question reads; use the given information given to find the exact value of the trigonometric function
cos theta (-3/5)
sin theta>0
{{{sin(t) = sqrt(1 - cos^2(t))}}}
{{{sin(t) = sqrt(1 - 9/25) = sqrt(16/25)}}}
sin(theta) = 4/5
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Find cos (theta/2)
Google half-angle formulas