Question 320855


{{{3x-2y=-16}}} Start with the given equation.



{{{-2y=-16-3x}}} Subtract {{{3x}}} from both sides.



{{{-2y=-3x-16}}} Rearrange the terms.



{{{y=(-3x-16)/(-2)}}} Divide both sides by {{{-2}}} to isolate y.



{{{y=((-3)/(-2))x+(-16)/(-2)}}} Break up the fraction.



{{{y=(3/2)x+8}}} Reduce.



So the equation {{{y=(3/2)x+8}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=3/2}}} and the y-intercept is {{{b=8}}} note: the y-intercept is the point *[Tex \LARGE \left(0,8\right)]