<PRE><B>Question 320801</B>
An airline has a policy of booking 21 passengers on a flight with 20 seats. Find the probability that there will not be enough seats available. The probability that a randomly selected person misses the flight is 5%.
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Binomial with n = 21 and p(misses) = 0.05 ; P(shows up) = 0.95
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P(x = 21) = 21C21(0.
binompdf(21,0.95,21) = 21C21*0.95^21 *0.05*0 = 0.95^21 = 0.3406
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Cheers,
Stan H.
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