Question 320805
As a condition of employment, Fashion Industries applicants must pass a drug test.
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Of the last 220 applicants 14 failed the test. 
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sample proportion = 14/220 = 0.6364
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Develop a 99 percent confidence interval for the proportion
of applicants that fail the test. 
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I ran a 1-Prop ZInt and got the following:
(0.0212, 0.1060)
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Would it be reasonable to conclude that more than
10 percent of the applicants are now failing the test? 
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No, > 10% is not in the 99% confidence interval
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In addition to the testing of applicants,
Fashion Industries randomly tests its employees throughout the year. Last year in the 400 random tests conducted, 14 employees failed the test.
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p-hat = 14/400 = 0.0350
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Would it be reasonable to conclude that less than 5 percent of the employees are not able to pass the random drug test?
Ho: p >= 0.05
Ha: p < 0.05 (claim)
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I ran a 1-Prop ZTest and got the following results:
test statistic: z = -1.3765
p-value = 0.0843
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Since the p-value is greater than 5%, fail to reject Ho.
Test results do not support the claim at the 5% significance level.
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Cheers,
stan H.