<PRE><B>Question 320658</B>
How many liters of a 45% acid solution must be added to 15 liters of a 30% acid solution to produce a 35% acid solution? 
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I&#39;m not sure what you are doing here, but let&#39;s think this out.
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Let x = amt of 45% solution to be added
then we know the resulting mixture will be (x+15), right?
Use the decimal equiv, write a typical mixture equation
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.45x + .30(15) = .35(x+15)
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.45x + 4.5 = .35x + 5.25
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.45x - .35x = 5.25 - 4.5
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.10x = .75
x = {{{.75/.1}}}
x = 7.5 liters to be added
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Check this in the original equation
.45(7.5) + .30(15) = .35(7.5+15)
3.375 + 4.5 = .35(22.5)
7.875 = 7.875; confirms our solution
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did this make sense to you?
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