Question 320637
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Let *[tex \Large x] represent the width.  Then the length must be: *[tex \Large 3x\ -\ 5].  The perimeter is two times the length plus two times the width.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2(3x\ -\ 5)\ +\ 2x\ = 94]


Solve for *[tex \Large x]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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