Question 320571
Simply plug in x=-2 and x=1 (separately) to evaluate f(-2) and f(1)


So {{{f(1) = 1^2+1=1+1=2}}} meaning that {{{f(1)=2}}} and {{{f(-2)=(-2)^2+1=4+1=5}}} making {{{f(-2)=5}}}