Question 320566
{{{x^2 + 6xy + 5y^2 =(3)^2 + 6(3)(5) + 5(5)^2 =9 + 6(3)(5) + 5(25)=9+90+125=224}}}



So {{{x^2 + 6xy + 5y^2 =224}}} when {{{x=3}}} and {{{y=5}}}