Question 320324
{{{(x^2-12x+32)/(x^2+3x-28)=((x-4)(x-8))/((x+7)(x-4))}}}
{{{(x^2-12x+32)/(x^2+3x-28)=(cross((x-4))(x-8))/((x+7)cross((x-4)))}}}
{{{(x^2-12x+32)/(x^2+3x-28)=(x-8)/(x+7)}}}