<PRE><B>Question 320175</B>
if the length and width are represented by l and w respectively,
 perimeter  = 2(l+w) = 208 ------- (1)
length is greater than width by 54 inches.
So, l = 54 + w ------- (2)

Substituting for l in (1), we get

2(54 + w + w) = 208
2(54 + 2w) = 208
Removing the brackets,
2X54 + 2X2w = 208
108  + 4w   = 208
       4w = 208 - 108
 or    4w = 100
 or     w = 100/4 = 25

So l = 54 + w = 54 + 25 = 79

Hence length = 79 inches and width = 25 inches.

[On cross checking, you can see that the length is 54 inches greater than the width and that the perimeter is 208 inches]</PRE>