Question 320157
Let {{{v=t^(-2)}}}, then {{{v^2=t^(-4)}}},
{{{2t^-4-5t^-2+2=2v^2-5v+2=0}}}
{{{2t^-4-5t^-2+2=(2v-1)(v-2)=0}}}
Two solutions:
{{{2v-1=0}}}
{{{2v=1}}}
{{{v=1/2}}}
{{{1/t^2=1/2}}}
{{{highlight(t=sqrt(2))}}}
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{{{v-2=0}}}
{{{v=2}}}
{{{1/t^2=2}}}
{{{t^2=1/2}}}
{{{highlight( t=sqrt(2)/2)}}}