Question 320096
{{{T= 2*pi*sqrt(L/32)}}}
Given T = 2 , find L
{{{2= 2*pi*sqrt(L/32)}}}
{{{2/(2*pi) = sqrt(L/32)}}}
{{{1/pi = sqrt(L/32)}}}
{{{0.318 = sqrt(L/32)}}}
{{{(0.318)^2 = L/32}}}
{{{32 * (0.318)^2 = L}}}
{{{3.24 = L}}} 
rounded to nearest tenth 3.2 feet
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