Question 4777
1.  Objects fall to earth at 32 feet per second. 
Distance/rate = time 

984/32 = 30.75 seconds

2. Use the pythagorean theorem
 {{{A^2  + B^2 = C^2}}}

First Leg = A
Second Leg = A+7
Hypotenuse = 35

{{{A^2  + (A+7)^2 = 35^2}}}

Clear your parentheses:

{{{A^2  + (A^2+14A+49) = 1225}}}
Subtract 1225 from both sides to set the equation = to zero

{{{2A^2 +14A + -1176 = 0}}}

Divide the equation by two (factor out a two):
{{{A^2 +7A + -588 = 0}}}

Then use the quadratic equation to solve

{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
{{{x = (-7 +- sqrt( 49-4*1*-588 ))/(2*1) }}} 
{{{x = (-7 +- sqrt( 49+2352 ))/(2) }}} 

Since we are talking about a measurement (a distance) we can disregard the negative answer,

{{{x = (-7 + sqrt( 2401))/(2) }}} = 21 feet
so the other leg is 28 feet