Question 37235
System.
2x+4y=10
3x-2y=-9
We can easily solve this system by reduction:

2x+4y=10
2(3x-2y)=2(-9)  We multiply the second equation by two getting a similar equation.

2x+4y=10
6x-4y=-18 We have the same system, now we only have to sum the corresponding parts.

       2x+4y=10
      +6x-4y=-18
Result:8x   =-8

Solving for x, 
8x=-8, x=-1
Substitution of x by its value,
2(-1)+4y=10
-2+4y=10
4y=12
y=3

The solutions to the system are, x=-1 and y=3