Question 319820
you are given two equations in two variables and asked to give the (x,y) form. It just means that you need to find the values of x and y and write them within single brackets.
Now the given equations are 
x+3y=2
2x-3y=22 
Now, in order to find the values of x and y, we have to obtain a single equation in either x or y from the given two equations. 
On comparing the two given equations we can see that the 'y' terms will get cancelled out by just adding the two of them.
i.e. x+3y+2x-3y=2+22 (add the left hand sides and the right hand sides separately)
or  x+2x+3y-3y=2+22 (bringing like terms together)
    3x+0=24 (since 3y-3y=0)
    3x = 24
     x = 24/3 = 8.
Now substitute this value of x in the first equation to get the value of y.
i.e. 8 + 3y = 2
      3y = 2 - 8 (on transposing, + 8 becomes - 8)
      3y = -6 
       y = -6/3
       y = -2.
SO the answer is (x,y) = (8,-2).