Question 319752
How many liters of a 20% alcohol solution should Maria mix with 50 liters of a 60% alcohol solution to obtain a 30% solution?
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Add x liters of 20%
The total volume will be x + 50
0.2x + 0.6*50 = (x + 50)*0.3 is the amount of alcohol
0.2x + 30 = 0.3x + 15
x = 150 liters