Question 319733
Since {{{5-8x=-(8x-5)}}} and {{{2-6x=-(6x-2)}}}, we can multiply the two right sides to get {{{(-(8x-5))(-(6x-2))=(8x-5)(6x-2)}}}



So multiplying {{{-(8x-5)}}} and {{{-(6x-2)}}} is the same as multiplying {{{8x-5}}} and {{{6x-2}}} which means that {{{(5 - 8x)(2 - 6x)}}} is also acceptable as an LCD.