Question 319722
Solve for x:
{{{Log[25](5) = x}}} Express this in exponential form: {{{Log[b](M) = N}}}--->{{{b^N = M}}}
{{{25^x = 5}}} Substitute {{{25 = 5^2}}}
{{{5^(2x) = 5^1}}} The bases (5) are equal so the exponents are equal:
{{{2x = 1}}} Divide by 2.
{{{highlight(x = 1/2)}}}