<PRE><B>Question 319714</B>
 given: 
P(x)=x^4-x^3-5x^2-x+6 
Find all real and non- real zeroes of P(x). 
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Note: Since the coefficients add up to zero, x = 1 is a zero.
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Use synthetic division to find other zeroes:
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1)....1....-1....-5....-1....6
.......1.....0.....-5....-6...|..0

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Quotient: x^3 -5x -6
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This quotient has a zero around x = 2.6891,
but that is the only Real zero my calculator
will pick up.
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It appears there are two complex zeroes, but
I cannot pin them down.
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Cheers,
Stan H.</PRE>