Question 319627
Each side of a rectangle increased by l%. The perimeter of the rectangle is
increased by
.
Let x=width
and y=length
.
Original perimeter is
2(x+y)
.
Increased by 1%
1.01x = width
1.01y = lenth
perimeter is:
2(1.01x + 1.01y) 
2*1.01(x+y)
2.02(x+y)
.
amount increased:
2.02(x+y) - 2(x+y)
(x+y)(2.02-2)
(x+y)(0.02)
0.02(x+y)
.
percent increased is then
[.02(x+y)]/[2(x+y)] * 100
[.02]/[2] * 100
.01 * 100
1%
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I copied and pasted Nerdy Bill's solution, and changed it from 10% to the requested 1%.
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Nerdy Bill used 10% increase (inadvertently) and got a 10% increase in perimeter.  I used 1%, and got a 1% increase in perimeter.
The perimeter is linearly related to the side lengths.  s*x --> p*x