Question 319627
Each side of a rectangle increased by l%. The perimeter of the rectangle is
increased by
.
Let x=width
and y=length
.
Original perimeter is
2(x+y)
.
Increased by 1%
1.1x = width
1.1y = lenth
perimeter is:
2(1.1x + 1.1y) 
2*1.1(x+y)
2.2(x+y)
.
amount increased:
2.2(x+y) - 2(x+y)
(x+y)(2.2-2)
(x+y)(0.2)
.2(x+y)
.
percent increased is then
[.2(x+y)]/[2(x+y)] * 100
[.2]/[2] * 100
.1 * 100
10%