<PRE><B>Question 319453</B>
Soybean meal is 18% protein; cornmeal is 9% protein.
 How many pounds of each should be mixed together in order to get 360-lb mixture that is 11% protein? 
:
Let x = amt of Soy
the result is to be 360 lb, therefore
(360-x) = amt of corn
:
An amt of protein equation
.18x + .09(360-x) = .11(360)
:
.18x + 32.4 - .09x = 39.6
:
.18x - .09x = 39.6 - 32.4
:
.09x = 7.2
x = {{{7.2/.09}}}
x = 80 lb of soy
and
360 - 80 = 280 lb of corn
:
:
Check solution in original mixture equation
.18(80) + .09(280) = .11(360)
14.4 + 25.2 = 39.6, confirms our solution</PRE>