Question 319226
A group of quality assurance personnel from the FDA sampled 41 low tar cigarettes from brand XYZ. The sample produced an average of 1.5 mg of nicotine with s = 0.33 mg. The national allowable average of nicotine in low tar cigarettes is 1.06 mg. Test the claim that the XYZ brand has a mean amount of nicotine that is greater than the allowable limit. (use a = 0.05)
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Ho: u = 1.06
Ha: u > 1.06
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x-bar = 1.5 
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t(1.5) = (1.5-1.06)/[0.33/sqrt(41)] = 8.5375
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p-value = P(t> 8.5375 when df=40) =7.5x10^-11
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Conclusion: Since the p-value is less than 5%,
reject Ho.
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Cheers,
Stan H.