Question 319278
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Factor Completely: 27z^3+125 

Use the sum of cubes formula: a^3 + b^3 = (a + b)(a^2 - 2b + b^2)

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27z^3 + 125 can be written as (3z)^3 + 5^3.

(3z)^3 + 5^3 = (3z + 5)(3z^2 - 3z*5 + 5^2)

(3z)^3 + 5^3 = (3z + 5)(3z^2 -15z + 25)

Done!