Question 319203
(1/4x^7)^3 (x^3)^6 
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Assuming the 4x^7 is in the denominator of the 1st fraction I get:
(1/(64x^21))*(x^18)
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= (1/64)(x^18/x^21)
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= (1/64)(1/x^3)
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= 1/(64x^3)
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Cheers,
Stan H.