Question 319178
{{{(x^2+4x-5)/(x+5)}}} Start with the given expression.



{{{((x+5)(x-1))/(x+5)}}} Factor the numerator.



{{{(highlight((x+5))(x-1))/highlight((x+5))}}} Highlight the common terms.



{{{(cross((x+5))(x-1))/cross((x+5))}}} Cancel out the common terms.



{{{x-1}}} Simplify.



So {{{(x^2+4x-5)/(x+5)}}} simplifies to {{{x-1}}}



This then means that {{{(x^2+4x-5)/(x+5)=x-1}}} where {{{x<>-5}}}