Question 319159
Since we have "an equation of the line passing through (-4, 4) with slope 5", we know that {{{m=5}}}, {{{x=-4}}} and {{{y=4}}}



{{{y=mx+b}}} Start with the general slope intercept equation.



{{{4=(5)(-4)+b}}} Plug in {{{m=5}}}, {{{x=-4}}} and {{{y=4}}}



{{{4=-20+b}}} Multiply 5 and -4 to get -20



{{{4+20=b}}} Add 20 to both sides.



{{{24=b}}} Add.



So the value of 'b' is {{{b=24}}}.



So {{{m=5}}} and {{{b=24}}}. Plug these values into {{{y=mx+b}}} to get {{{y=5x+24}}}



So the equation of the line with slope 5 which goes through (-4,4) is {{{y=5x+24}}}