Question 318155
{{{a^2+b^2=10^2=100}}}
{{{b^2=100-a^2}}}
There are an infinite number of possible choices for a and b.
Let {{{a=1}}}
Then {{{b^2=100-1=99}}}, {{{b=sqrt(99)}}}
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Let {{{a=5}}}
Then {{{b^2=100-25=75}}}, {{{b=sqrt(75)=5sqrt(3)}}}
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If {{{a=b}}}, then
{{{2a^2=100}}}
{{{a^2=50}}}
{{{a=b=sqrt(50)=5sqrt(2)}}}