Question 319104
Hopefully we're on the Brazilian or German team and not the English or Italian team!
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Each person has the same probability.
Each time a person is chosen the total possible choices reduces by 1.
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P(me)=1/180
P(1st friend)=1/179
P(2nd friend)=1/178
P(3rd friend)=1/177
P(4th friend)=1/176
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To find the total, multiply all of the probabilities. 
{{{P=5.6x10^(-12)}}}
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We could have also look at all of the permutation without repetition for 5 items chosen from a pool of 180.
The number of permutations is,
{{{N=(180!)/(180-5)!=180*179*178*177*176}}}
Our specific permutation was one of those so the probability was 
{{{P=1/(180*179*178*177*176)}}}
which is the same result.

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Usually it's not that random of a process, but watching some of the World Cup play it seems like some teams might be using that method.