Question 318989
convert to a logarithmic equation 

e^-2=0.1352
<pre><b>
Learn that the exponential equation 

{{{B^A=C}}} 

is equivalent to the logarithm equation 

{{{log(B,(C))=A}}}

The logarithm = the exponent
The base of the exponent is the base of the logarithm
 and 
The result of the exponential is what the log is taken of.

Using that rule:

{{{e^(-2)=0.1352}}} becomes

{{{log(e,(0.1352))=-2}}}

But {{{"ln"}}} is short for {{{log(e,"")}}}

So the final answer is:

{{{ln(0.1352)=-2}}}

Edwin</pre>