Question 318988
Use logarithms.
{{{(0.6)^x=125/27}}}
{{{x=log(0.6,(125/27))}}}
{{{x=log((125/27))/log((0.6))}}}
{{{x=0.66555/(-0.22185)}}}
{{{highlight(x=-3)}}}
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You could also have noticed that.
{{{(3/5)^y=(27/125)}}} 
and {{{3^3=27}}} and {{{5^3=125}}}
{{{y=3}}}
Since it was the reciprocal, the exponent would have been (-3).
{{{x=-y=-3}}}.