Question 36086
  -4<5+x<0  and x<0 Because it is negative

-4=5+x
-9=x   Therefore x must be greater than -9 

5+x=0
x=-5   Therefore x must be less than -5

   The solution of the problem is the open interval of the numbers greater than -9 and less than -5,  S=(-6,-7,-8)  Are the threes negative integers that are solution to the problem.