Question 319088
The diagonal of the square is 4.
2a^2=c^2 Pythagoras
2a^2=16
a^2=8
a=sqrt(4*2)
=2sqrt(2) side of square
a^2=8 area of square
.
A=pi*r^2
=pi area of one of the circles
2pi area of both circles
.
8-2pi= area between the circles and the square.
.
Ed